A solid sphere of mass 2 kg and radius 5 cm is rotating at the rate of 300 rpm. The torque required to stop it in 2pi revolutions is
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![What will be the pressure in dyne cm^-2 , due to a water column of height 10cm ? [take g = 980cm/s^2 ] (density of water = 10^3kg m^-3 ).](https://dwes9vv9u0550.cloudfront.net/images/2485706/ed4284a0-8615-4be0-9398-e2024f567486.jpg "What will be the pressure in dyne cm^-2 , due to a water column of height 10cm ? [take g = 980cm/s^2 ] (density of water = 10^3kg m^-3 ).")
What will be the pressure in dyne cm^-2 , due to a water column of height 10cm ? [take g = 980cm/s^2 ] (density of water = 10^3kg m^-3 ).
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Convert (i) 1Nm^(2)kg^(-2) into dyne cm^(2)g^(-2), (ii) 60Kmhr^(-1) into ms^(-1),
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A sphere of mass 2000 g and radius 5 cm is rotating at the rate of 300 rpm . Then the torque required to stop it in 2pi revolutions, is
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Convert the value of G=6 67*10^-11 Nm^2kg^-2 into CGS unit - Physics - Motion In A Straight Line - 13932631 | Meritnation.com
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The value of gravitation is `G = 6.67 xx 10^(-11)N-m^(2)/kg^(2)` in SL units . Convert it into C... - YouTube
A pressure of `10^(6)" dyne"//cm^(2)` is equivalent to : - YouTube
Young's modulus of steel is 19 × 10^10Nm^-2 . Its value in dyne cm^-2 is:
The value of G = 6.67 × 10^-10Nm^2(kg)^-2 its numerical value in CGS system will be
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Newton to dyne, dyne to Newton - YouTube
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A body of mass m is floating in a liquid of density d.a) What is the apparent weight of the body?b) What is the loss of weight of the body?
The value of universal gravitational cosntant G in CGS system is 6.67 × 10^-8 dyne cm^2gm^-2 . Its value in SI system is :
